Examples for Practice: Statics of Particles - Engineering Mechanics
Example 2.4.1 Find x and y components of the 6 forces shown in Fig. 2.4.1. Also write the forces in terms of unit vector î and ĵ along x and y directions respectively. Solution: Example 2 4.2 Find x and y components of the forces shown in Fig. 2.4.2. Solution: When slopes are given for the forces, their angles with horizontal can be obtained using Example 2.4.3 Find the x and y components of a 1000 N force acting from the point (-3, 5) of a 1000 N force acti towards the point (6. – 3). Solution: The angle of the force with horizontal can be calculated by plotting it as shown in Fig. 2.4.3. Example 2.4.4 Find the magnitude and direction of forces having x and y components as shown in Fig. 2.4.4 (a) to (d). Solution: For Fig. 2.4.4 (a), Example 2.4.5 Find components Fa and Fb of the 100 N force along the directions shown in Fig. 2.4.5 using rectangular components. Solution: • As 100 N force is being resolved into components Fa and Fb the 100 N force will be a resultant of Fa and Fb. • For rectangular components, X and Y directions are required which can be chosen according to convenience. • Let X-axis be along the 100 N force and Y-axis perpendicular to it as shown in Fig. 2.4.5 (a). Example 2.4.6 Determine the resultant of the five forces shown in Fig. 2.4.6. Solution : Resolving forces in X and Y directions, Example 2.4.7 If the resultant of the two forces shown in Fig. 2.4.7 is 700 N directed vertically upwards, find the angles a and B using rectangular components. Solution: Choosing X-axis horizontal and Y-axis vertical. As resultant is vertical, its x component is 0 and y component is 700 N. 25 = 16+ 49 - 56 cos β 56 cos β = 40 Examples for Practice Q.1 A force F1 = 1200 N is acting vertically on an incline [Refer Fig. 2.4.8]. Find its components along X and Y axes. [Ans.: F1x = -720N, F1y = -960N] Q.2 A force of 200 N is acting on a block as shown in Fig. 2.4.9. Find the component of force along the horizontal and vertical axis. [Ans.: Fx = 100 N, Fy = 173.2.N] Q.3 Find x and y components of forces shown in Fig. 2.4.10. [Ans.: F1x = -150N, F1y = 200N F2x = 89.44 N, F2y =178.89 N, F3x = -60N, F3y = 80N] Q.4 Determine the x and y components of a force of magnitude 50 N acting from point A(1,4) towards B(- 2, 8). Also write the force vector in terms of unit vectors along x and y direction. [Ans. : Fx = -30 N, Fy = 40 N, Q.5 Determine the magnitude and direction of the forces having x and y components given below: Q.6 Determine components Fa and Fb of the 500 N force along the directions shown in Fig. 2.4.11. using rectangular components. [ Ans. : Fa = 442.28 N, Fb = 542.53 N] Q.7 Find the resultant of coplanar concurrent force system shown in Fig. 2.4.12. [Ans. : R = 459.8 N, 51.24° Q.8 If the resultant of the two forces shown in Fig. 2.4.13. is 90 kN directed vertically upwards, find the angles α and β using rectangular components. [Ans. : α = 39.29°, β = 56.44°]Solved Examples for Understanding
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Engineering Mechanics: Unit I: Statics of Particles : Tag: : Statics of Particles | Engineering Mechanics - Solved Example & Practice Problems: Resolution and Composition of Forces: Rectangular Components
Engineering Mechanics
ME3351 3rd semester civil, Mechanical Dept | 2021 Regulation | 3rd Semester Mechanical Dept 2021 Regulation