Materials Science: Unit II(b): Magnetic Properties of Materials
Anna University Solved Problems
Magnetic Properties of Materials | Materials Science
Anna University Solved Problems: Problems with solutions: Electrical and Magnetic Properties of Materials: Materials Science
ANNA UNIVERSITY SOLVED PROBLEMS 1. A magnetic field strength of 2 × 105 amperes / metre is applied to a paramagnetic material with a relative permeability of 1.01. Calculate the values of B and M Given data Magnetic field strength H = 2 × 105 A/m Relative permeability μr = 1.01 Solution We know that M / H = μr -1 M = H (μr - 1) Substituting the given values, we have = 2 × 105 (1.01 – 1) M = 2 × 103 B = μo (M + H) = 4π × 10-7 (2 × 103 + 2 × 105) = 4π × 10-7 (0.02 × 105 + 2 × 105) = 4 π × 10-7 (2.02 × 105) B = 0.2537 Wbm2 2. Magnetic field intensity of a paramagnetic material is 104 ampere/metre. At room temperature its susceptibility is 3.7 × 10-3. Calculate the magnetization of the material. Given data Magnetic field intensity H = 104 ampere / metre Susceptibility χ = 3.7 × 10-3 Magnetization of the material = ? Solution We know that Magnetization = χ H Substituting the given values, we have = 3.7 × 10-3 × 104 M = 37 ampere / metre
Materials Science: Unit II(b): Magnetic Properties of Materials : Tag: : Magnetic Properties of Materials | Materials Science - Anna University Solved Problems
Materials Science: Unit II(b): Magnetic Properties of Materials
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