Transforms and Partial Differential Equations: Unit II: Fourier Series

Parseval's relation (or) theorem (or) identity

Definition, Solved Example Problems | Fourier Series

Definition: Root Mean Square Value [RMS Value] (or) Effective value

PARSEVAL'S RELATION (or) THEOREM (or) IDENTITY


Definition: Root Mean Square Value [RMS Value] (or) Effective value


Note: Parseval's theorem gives the values of root mean square of f (x) in terms of its Fourier coefficients.

Problems based on Parseval's theorem

Example 2.5.1 : Obtain the Fourier series expansion of f(x) = x2 in (-1, 1). Find the sum of

Solution : ƒ(-x) = f(x)

Therefore f(x) is an even function. Hence bn = 0


By Parseval's theorem,


Example 2.5.2 : Find the sine series for ƒ (x) = x in 0 < x < л. Using R.M.S. value, show that

Solution: See the value ba in Example 2.3.a(1)


Using R.M.S. value


Example 2.5.3: Find the Fourier series x2 in (-л, л). Use Рarsevals identity to prove

Solution :


Example 2.5.4 : Find the cosine series for f(x) = x in (0, л) and then using Parseval's theorem.


Solution :


Example 2.5.5: Find the half range cosine series of f (x) = (π - x2) in the interval (0,л). Hence find the sum of the series

Solution: See Page No. 2.137 the values in Example 2.3.b(7)


Example 2.5.6: Find the half-range cosine series for the function f(x) = x (л − x) in 0 < x < л. Deduce that


Solution : See the values in Example 2.3.b(8)



EXERCISES 2.5


Transforms and Partial Differential Equations: Unit II: Fourier Series : Tag: : Definition, Solved Example Problems | Fourier Series - Parseval's relation (or) theorem (or) identity